Hacker Newsnew | past | comments | ask | show | jobs | submitlogin

It’s not that much, actually. The average English word is 4.7 letters long. Let’s round up to 5 and add 1 for a space to make 6 characters. Novels are around 90,000 words long. So 800G of pure text represents 800G / 6 char per word / 90,000 words per book =~ 1.5M books. The Library of Congress has 39M books, not to mention all the text produced that’s exclusively online.


That makes me wonder what's the upper bound of storage required to contain all of the text humans had ever written. 1k times as much? 10k? Either way, I have a feeling that all of the drives would probably fit in a regular apartment room.

Crazy how we went from first computers spanning across entire floors to fitting all of human thoughts in such tight space.


The entire Library of Congress according to the earlier calculations would fit into 21 TB. There's already a 100 TB SSD that's the size of a 3.5" HDD.[0] 10000 times the Library of Congress would fit onto 2100 of these drives.

The dimensions for this 3.5" drive are 26.1 x 147 x 101.8 mm.[1] That's a volume of roughly 391 cm^3. 2100 of them take up 821,100 cm^3.

A Fractal Design Define 7 has the dimensions of 547 x 240 x 475 mm. That's a volume of 62,358 cm^3.[2]

You could fit 2100 of those SSDs into the same volume as about 13.2 Fractal Design Define 7 cases. That's roughly the size of a bookshelf. You could fit the books of 10000 Libraries of Congress onto one bookshelf.

Now imagine using tape for this. Edit: I'm actually not sure whether tape has better density.

[0] https://www.techradar.com/news/at-100tb-the-worlds-biggest-s...

[1] https://www.newegg.com/nimbus-data-dc-100tb/p/2U3-002M-00004

[2] https://www.tomshardware.com/reviews/fractal-design-define-7




Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: