17.3 kJ for the latest shot, according to the paper. But only some 8 kJ of that came from fusion (the balance came from the laser input).
D-T fusions are about 17.6 MeV, but 80% of that is in neutrons, which escape unless captured in a special blanket. The 8 kJ reported was all alphas. So 8 kJ / 3.5 MeV = 1.4e16 fusions, vs. 5e15 in the quote. He was probably talking about a previous shot.
For comparison, a typical AA battery stores 16 kJ.
You're misreading. E_{DT} is not the D+T fusion yield; it is the heat absorbed by the D+T fuel target (sum of external heating and self-heating from fusion alphas). E_{fusion} is the fusion yield.
E_{fusion} is the calculated neutron yield Y_{total}=6.1e15 times 17.6 MeV: 17.2 kJ + rounding. Check out page 3, right column.
D-T fusions are about 17.6 MeV, but 80% of that is in neutrons, which escape unless captured in a special blanket. The 8 kJ reported was all alphas. So 8 kJ / 3.5 MeV = 1.4e16 fusions, vs. 5e15 in the quote. He was probably talking about a previous shot.
For comparison, a typical AA battery stores 16 kJ.